1.1=2x+4.9x^2

Solution for 1.1=2x+4.9x^2 equation:

1.1=2x+4.9x^2

We move all terms to the left:

1.1-(2x+4.9x^2)=0

We get rid of parentheses

-4.9x^2-2x+1.1=0

a = -4.9; b = -2; c = +1.1;
Δ = b2-4ac
Δ = -22-4·(-4.9)·1.1
Δ = 25.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{25.56}}{2*-4.9}=\frac{2-\sqrt{25.56}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{25.56}}{2*-4.9}=\frac{2+\sqrt{25.56}}{-9.8}
$